(y^2+2xy)dx-(xy+x^2)dy=0

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Solution for (y^2+2xy)dx-(xy+x^2)dy=0 equation:


Simplifying
(y2 + 2xy) * dx + -1(xy + x2) * dy = 0

Reorder the terms:
(2xy + y2) * dx + -1(xy + x2) * dy = 0

Reorder the terms for easier multiplication:
dx(2xy + y2) + -1(xy + x2) * dy = 0
(2xy * dx + y2 * dx) + -1(xy + x2) * dy = 0

Reorder the terms:
(dxy2 + 2dx2y) + -1(xy + x2) * dy = 0
(dxy2 + 2dx2y) + -1(xy + x2) * dy = 0

Reorder the terms for easier multiplication:
dxy2 + 2dx2y + -1dy(xy + x2) = 0
dxy2 + 2dx2y + (xy * -1dy + x2 * -1dy) = 0
dxy2 + 2dx2y + (-1dxy2 + -1dx2y) = 0

Reorder the terms:
dxy2 + -1dxy2 + 2dx2y + -1dx2y = 0

Combine like terms: dxy2 + -1dxy2 = 0
0 + 2dx2y + -1dx2y = 0
2dx2y + -1dx2y = 0

Combine like terms: 2dx2y + -1dx2y = 1dx2y
1dx2y = 0

Solving
1dx2y = 0

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Divide each side by '1'.
dx2y = 0

Simplifying
dx2y = 0

The solution to this equation could not be determined.

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